Advertisements
Advertisements
Question
Shown in the figure is rigid and uniform one meter long rod AB held in horizontal position by two strings tied to its ends and attached to the ceiling. The rod is of mass 'm' and has another weight of mass 2m hung at a distance of 75 cm from A. The tension in the string at A is :
Options
0.75 mg
1 mg
0.5 mg
2 mg
MCQ
Solution
1 mg
Explanation:
Given: Length of rod AB is L = 1 m, mass of the rod is m the rod is hanging with two strings, tied at ends A and B.
To find: TA, the tension in the string tied at end A.
As the rod is in equilibrium the torque about point B is zero.
TA× 100 - mg × 50 - 2 mg × 25 = 0
TA = 1 mg
shaalaa.com
Reflection of Waves - Standing Waves and Normal Modes
Is there an error in this question or solution?