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Question
Simplify:
Solution
\[\left[ \left\{ \left( \frac{- 1}{4} \right)^2 \right\}^{- 2} \right]^{- 1}\] `=(((-1)^2/4^2)^(-2))^(-1)` → ((a/b)n = an/(bn))
`=(((1)/16)^(-2))^(-1)` → (a−n = 1/(an))
`=(((1)/(1/16)^2)^(-2))^(-1)`
`=((1)/(1/256))^(-1)`
`=256^(-1)` → (a−1 = 1/a)
`=1/256`
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