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Question
Simplify and express as positive indice:
`[(32"x"^-5)/(243"y"^-5)]^(-1/5)`
Sum
Solution
`[(32"x"^-5)/(243"y"^-5)]^(-1/5)=[(2^5xx"x"^-5)/(3^5"y"^-5)]^(-1/5)`
`=[2^(5xx(-1)/5)."x"^(-5xx(-1)/5))/(3^(5xx(-1)/5)."y"^-5xx(-1)/5)`
`=(2^-1"x"^(+1))/(3^-1"y"^(+1)`
`=(3"x")/(2"y")`
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Law of Exponents (For Integral Powers)
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