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Question
`int (sin^2x - cos^2x)/(sin^2x cos^2x) dx` is equal to
Options
`tan x + cot x + c`
`tan x + "cosec" x + c`
`- tan x + cot x + c`
`tan x + sec x + c`
MCQ
Solution
`tan x + cot x + c`
Explanation:
I = `int (sin^2x - cos^2x)/(sin^2 x cos^2x) dx`
= `int ((sin^2x)/(sin^2x cos^2x) - (cos^2x)/(sin^2x cos^2x))`
= `int (1/(cos^2x) = 1/(sin^2x)) dx`
= `int (sec^2x - "cosec"^2x) dx`
= `tan x + cot x + c`
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