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Sincotcostanxsin[cot-1{cos(tan-1 x)}]= ____________. -

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Question

`"sin" ["cot"^-1 {"cos" ("tan"^-1  "x")}] =` ____________.

Options

  • `sqrt(("x"^2 + 1)/("x"^2 + 2))`

  • `sqrt(("x"^2 - 1)/("x"^2 - 2))`

  • `sqrt(("x" - 1)/("x" - 2))`

  • `sqrt(("x" + 1)/("x" + 2))`

MCQ
Fill in the Blanks

Solution

`"sin" ["cot"^-1 {"cos" ("tan"^-1  "x")}] =``underline(sqrt(("x"^2 + 1)/("x"^2 + 2))`.

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