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Solve the Following Equation and Verify Your Answer: 15 ( 2 − X ) − 5 ( X + 6 ) 1 − 3 X = 10 - Mathematics

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Question

Solve the following equation and verify your answer:

\[\frac{15(2 - x) - 5(x + 6)}{1 - 3x} = 10\]
Sum

Solution

\[\frac{2x - (7 - 5x)}{9x - (3 + 4x)} = \frac{7}{6}\]

\[\text{ or }\frac{7x - 7}{5x - 3} = \frac{7}{6}\]

\[\text{ or }42x - 42 = 35x - 21 [\text{ After cross multiplication }]\]

\[\text{ or }42x - 35x = - 21 + 42\]

\[\text{ or }7x = 21\]

\[\text{ or }x = \frac{21}{7}\]

\[\text{ or }x = 3\]

\[\text{ Thus, }x = 3\text{ is the solution of the given equation . }\]

\[\text{ Check: }\]

\[\text{ Substituting }x = 3\text{ in the given equation, we get: }\]

\[\text{ L . H . S . }= \frac{2 \times 3 - (7 - 5 \times 3)}{9 \times 3 - (3 + 4 \times 3)} = \frac{6 - (7 - 15)}{27 - (3 + 12)} = \frac{6 + 8}{27 - 15} = \frac{14}{12} = \frac{7}{6}\]

\[\text{ R . H . S . }= \frac{7}{6}\]

\[ \therefore\text{ L . H . S . = R . H . S . for }x = 3 .\]

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Chapter 9: Linear Equation in One Variable - Exercise 9.3 [Page 17]

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RD Sharma Mathematics [English] Class 8
Chapter 9 Linear Equation in One Variable
Exercise 9.3 | Q 19 | Page 17

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