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Question
Solve the following equation and verify your answer:
Solution
\[\frac{2x - (7 - 5x)}{9x - (3 + 4x)} = \frac{7}{6}\]
\[\text{ or }\frac{7x - 7}{5x - 3} = \frac{7}{6}\]
\[\text{ or }42x - 42 = 35x - 21 [\text{ After cross multiplication }]\]
\[\text{ or }42x - 35x = - 21 + 42\]
\[\text{ or }7x = 21\]
\[\text{ or }x = \frac{21}{7}\]
\[\text{ or }x = 3\]
\[\text{ Thus, }x = 3\text{ is the solution of the given equation . }\]
\[\text{ Check: }\]
\[\text{ Substituting }x = 3\text{ in the given equation, we get: }\]
\[\text{ L . H . S . }= \frac{2 \times 3 - (7 - 5 \times 3)}{9 \times 3 - (3 + 4 \times 3)} = \frac{6 - (7 - 15)}{27 - (3 + 12)} = \frac{6 + 8}{27 - 15} = \frac{14}{12} = \frac{7}{6}\]
\[\text{ R . H . S . }= \frac{7}{6}\]
\[ \therefore\text{ L . H . S . = R . H . S . for }x = 3 .\]
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