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Question
Solve the following equation and verify your answer:
Solution
\[\frac{2y + 5}{y + 4} = 1\]
\[\text{ or }2y + 5 = y + 4\]
\[\text{ or }2y - y = 4 - 5\]
\[\text{ or }y = - 1\]
\[\text{ Thus, } y = - 1\text{ is the solution of the given equation . }\]
\[\text{ Check: }\]
\[\text{ Substituting }y = - 1 \text{ in the given equation, we get: }\]
\[\text{ L . H . S . }= \frac{2( - 1) + 5}{- 1 + 4} = \frac{- 2 + 5}{3} = \frac{3}{3} = 1\]
\[\text{ R . H . S . }= 1\]
\[ \therefore\text{ L . H . S . = R . H . S . for }y = - 1 .\]
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