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Question
Solve the following equation and verify your answer:
Solution
\[\frac{x + 2}{x + 5} = \frac{x}{x + 6}\]
\[\text{ or }x^2 + 2x + 6x + 12 = x^2 + 5x [\text{ After cross multiplication }]\]
\[\text{ or }x^2 - x^2 + 8x - 5x = - 12\]
\[\text{ or }3x = - 12\]
\[\text{ or }x = \frac{- 12}{3}\]
\[\text{ or }x = - 4\]
\[\text{ Thus, }x = - 4 \text{ is the solution of given equation . }\]
\[\text{ Check: }\]
\[\text{ Substituting }x = - 4\text{ in the given equation, we get: }\]
\[\text{ L . H . S .} = \frac{- 4 + 2}{- 4 + 5} = - 2\]
\[\text{ R . H . S . }= \frac{- 4}{- 4 + 6} = - 2\]
\[ \therefore\text{ L . H . S . = R . H . S . for }x = - 4 .\]
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