Advertisements
Advertisements
Question
Solve the following equation: `x^2 + (a + 1/a)x + 1 = 0`
Solution
`x^2 + (a + 1/a)x + 1 = 0`
`x^2 + ax + 1/a x + 1 = 0`
`x (x + a) + 1/a (x + a) = 0`
`(x + a)(x + 1/a) = 0`
x = -a , x = `- 1/a`
APPEARS IN
RELATED QUESTIONS
Find x in terms of a, b and c: `a/(x-a)+b/(x-b)=(2c)/(x-c)`
Solve the following quadratic equations
(i) x2 + 5x = 0 (ii) x2 = 3x (iii) x2 = 4
Solve for x :
`1/(x + 1) + 3/(5x + 1) = 5/(x + 4), x != -1, -1/5, -4`
If an integer is added to its square, the sum is 90. Find the integer with the help of quadratic equation.
Solve the following quadratic equation by factorisation.
\[25 m^2 = 9\]
If the equation x2 − ax + 1 = 0 has two distinct roots, then
Solve the following equation: c
Solve the Following Equation : x2- x - a (a + 1) = o
The length of verandah is 3m more than its breadth. The numerical value of its area is equal to the numerical value of its perimeter.
(i) Taking x, breadth of the verandah write an equation in ‘x’ that represents the above statement.
(ii) Solve the equation obtained in above and hence find the dimension of verandah.
Solve the following equation by factorization
`x/(x + 1) + (x + 1)/x = (34)/(15)`