Question

Solve the following quadratic equations by factorization:

`10x-1/x=3`

Answer 1

We have

`10x-1/x=3`

`rArr(10x^2-1)/x=3`

⇒ 10x² - 1 = 3x

⇒ 10x² - 3x - 1 = 0

⇒ 10x² - 5x +2x - 1 = 0

⇒ 5x(2x - 1) + 1(2x - 1) = 0

⇒ (2x - 1)(5x + 1) = 0

⇒ 2x - 1 = 0 or 5x + 1 = 0

⇒ 2x = 1 or 5x = -1

⇒ x = 1/2 or x = -1/5

Hence, x = 1/2 or x = -1/5