Question

Solve the following quadratic equations by factorization:

`x^2-(sqrt2+1)x+sqrt2=0`

Answer 1

We have,

`x^2-(sqrt2+1)x+sqrt2=0`

`rArrx^2-sqrt2x-x+sqrt2=0`

`rArrx(x-sqrt2)-1(x-sqrt2)=0`

`rArr(x-sqrt2)(x-1)=0`

`rArrx-sqrt2=0`

`rArrx=sqrt2`

⇒ x - 1 = 0

⇒ x = 1

Hence, `x=sqrt2` or x = 1