Question

Solve the following quadratic equations by factorization:

`x^2-(sqrt3+1)x+sqrt3=0`

Answer 1

We have,

`x^2-(sqrt3+1)x+sqrt3=0`

`rArrx^2-sqrt3x-x+sqrt3=0`

`rArrx(x-sqrt3)-1(x-sqrt3)=0`

`rArr(x-sqrt3)(x-1)=0`

`rArrx-sqrt3=0`

`rArrx=sqrt3`

or,

⇒ x - 1 = 0

⇒ x = 1

Hence, `x=sqrt3` or x = 1