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Question
Solve the following systems of equations:
`5/(x - 1) + 1/(y - 2) = 2`
Solution
Let us put` 1/(x - 1) = p and 1/(y - 2) = q` The the given equation
`5(1/(x - 1)) + 1/(y - 2) = 2` .....(1)
`6(1/(x - 1)) -3 (1/(y - 2) ) = 1` ....(2)
Can be written as
5p + q = 2 ....(3)
6p - 3q = 1 ...(4)
Equation 3 and 4 from a pair of linear equations in the genera; form. Now you can use any method to solve these equation we get p = 1/3 and q = 1/3 now
substituting `1/(x - 1)` fpr p we have
`1(x - 1) = 1/3`
i.e x - 1 = 3 i.e x = 4
Similary substituting 1/(y -2) for q we get
`1/(y -2) = 1/3`
i.e 3 = y - 2 i.e y = 5
Hence x = 4, y = 5 is required solution of the given pair of euation
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