Advertisements
Advertisements
Question
Solve the following differential equation:
Suppose that the quantity demanded Qd = `13 - 6"p" + 2 "dp"/"dt" + ("d"^2"p")/("dt"^2)` and quantity supplied Qs = `- 3 + 2"p"` where p is the price. Find the equilibrium price for market clearance
Solution
For market clearance, the required condition is Qd = Qs
`13 - 6"p" + 2 "dp"/"dt" + ("d"^2"p")/("dt"^2) = - 3 + 2"p"`
`("d"^2"p")/("dt"^2) + 2 "dp"/"dt" - 6"p" + 13 + 3 = 0`
`("d"^2"p")/("dt"^2) + 2 "dp"/"dt" - 8"p" = - 16`
`("D"^2 + 2"D" - 8)"p" = - 16`
The auxiliary equation is
m2 + 2m – 8 = 0
(m + 4)(m – 2) = 0
m = – 4, 2
Roots are real and different
C.F = Aem1t + Bem2t
C.F = `"Ae"^(- 4"t") + "BE"^(2"t")`
P.I = `1/(("D"^2 + 2"D" - 8)) (- 16)`
= `1/(("D"^2 + 2"D" - 8)) (- 16 "e"^(0_x))`
= `1/((0 + 2(0) - 8)) (- 16 "e"^(0_x))`
= `(-16)/(- 8)`
P.I = 2
The general solution is y = C.F + P.I
P = `"Ae"^(-4"t") + "Be"^(2"t") + 2`
APPEARS IN
RELATED QUESTIONS
Solve the following differential equation:
(D2 – 2D – 15)y = 0 given that `("d"y)/("d"x)` = 0 and `("d"^2y)/("d"x^2)` = 2 when x = 0
Solve the following differential equation:
(4D2 + 4D – 3)y = e2x
Solve the following differential equation:
(D2 – 3D + 2)y = e3x which shall vanish for x = 0 and for x = log 2
Solve the following differential equation:
(3D2 + D – 14)y – 13e2x
Choose the correct alternative:
The complementary function of (D2 + 4) y = e2x is
Choose the correct alternative:
The particular intergral of the differential equation `("d"^2y)/("d"x^2) - 8 ("d"y)/("d"x) + 16y = 2"e"^(4x)`
Choose the correct alternative:
The integrating factor of `x ("d"y)/("d"x) - y = x^2` is
Choose the correct alternative:
The complementary function of `("d"^2y)/("d"x^2) - ("d"y)/("d"x) = 0` is
Choose the correct alternative:
The general solution of the differential equation `("d"y)/("d"x) = cos x` is
Suppose that Qd = `30 - 5"P" + 2 "dP"/"dt" + ("d"^2"P")/("dt"^2)` and Qs = 6 + 3P. Find the equilibrium price for market clearance