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Solve the following problem. The heating element connected to 230V draws a current of 5A. Determine the amount of heat dissipated in 1 hour (J = 4.2 J/cal.). - Physics

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Question

Solve the following problem.

The heating element connected to 230V draws a current of 5A. Determine the amount of heat dissipated in 1 hour (J = 4.2 J/cal.).

Sum

Solution

Given: V = 230 V, I = 5 A, Δt = 1 hour = 60 × 60 sec

To find: Heat dissipated (H)

Formula: H = ΔU = IΔtV

Calculation: From the formula,
H = 5 × 60 × 60 × 230
= 4.14 × 106 J
Heat dissipated in calorie,
H = `(4.14xx10^6)/4.2` = 985.7 × 103 cal
= 985.7 kcal

The amount of heat dissipated in 1 hour is 985.7 kcal.

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Chapter 11: Electric Current Through Conductors - Exercises [Page 220]

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Balbharati Physics [English] 11 Standard Maharashtra State Board
Chapter 11 Electric Current Through Conductors
Exercises | Q 4. (xii) | Page 220
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