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Question
Solve `x = (3x + 1)/(4x)`
Sum
Solution
`x = (3x + 1)/(4x)`
`=> 4x^2 = 3x + 1`
`=> 4x^2 - 3x - 1 = 0`
`=> 4x^2 - 4x + x - 1 = 0`
`=> 4x(x - 1) + 1(x - 1) = 0`
=> (x - 1)(4x + 1) = 0
Since x - 1 = 0 or 4x + 1 = 0
then x = 1 or x = `(-1)/4`
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