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Question
Solve for x : `"x"/4 + 3 <= "x"/3 + 4` , where xis a negative odd number.
Solution
`"x"/4 + 3 <= "x"/3 + 4`
`("x" + 12)/4 <= ("x" + 12)/3`
3x + 36 ≤ 4x + 48
3x- 4x ≤ 48- 36
- x ≤ 12
x ≥ -12
Solution set = { -11 -9 -7 -5 -3 - 1}
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