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Question
Solve for x and y:
3x - 5y - 19 = 0, -7x + 3y + 1 = 0
Solution
The given system of equation is:
3x - 5y - 19 = 0 ……(i)
-7x + 3y + 1 = 0 ……(ii)
On multiplying (i) by 3 and (ii) by 5, we get:
9x - 15y = 57 ……(iii)
-35x + 15y = -5 …….(iv)
On subtracting (iii) from (iv) we get:
-26x = (57 – 5) = 52
⇒x = -2
On substituting the value of x = -2 in (i), we get:
–6 – 5y – 19 = 0
⇒5y = (–6 – 19) = -25
⇒y = -5
Hence, the solution is x = -2 and y = -5.
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