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Question
सरल रूप दो।
`(2/3)^6 div (2/3)^9`
Simplify
Solution
`(2/3)^6 div (2/3)^9`
`= (2/3)^(6-9)` ...[∵ am ÷ an = am-n]
`= (2/3)^(-3)`
= `(3/2)^3` ....`[∵ "a"^-"m" = 1/"a"^"m"]`
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Chapter 4.4: बैजिक व्यंजक और उनपर की जाने वाली संक्रियाएँ - प्रकीर्ण प्रश्नसंग्रह 1 [Page 93]
