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Question
Starting with the same initial conditions, an ideal gas expands from volume V1 to V2 in three different ways. The work done by the gas is W1 if the process is purely isothermal, W2, if the process is purely adiabatic and W3 if the process is purely isobaric. Then, choose the correct option.
Options
W1 < W2 < W3
W2 < W3 < W1
W3 < W1 < W2
W2 < W1 < W3
MCQ
Solution
W2 < W1 < W3
Explanation:
When we look at the area under the given figure, we get:
A3 > A1 > A2
Hence, W3 > W1 > W2
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Equation of State of a Perfect Gas
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