Advertisements
Advertisements
Question
State and explain Pauli's exclusion principle.
Solution
Pauli’s exclusion principle states that “No two electrons in an atom can have the same set of values of all four quantum numbers”.
Illustration: H(Z = 1) 1s1.
One electron is present in hydrogen atom, the four quantum numbers are n = 1, l = 0, m = 0 and s = `+1/2`. For helium Z = 2. He: 1s2. In this one electron has the quantum number same as that of hydrogen, n = 1, l = 0, m = 0 and s = `+1/2` For other electron, fourth quantum number is different, i.e. n = 1, l = 0, m = 0 and s = `-1/2`.
APPEARS IN
RELATED QUESTIONS
Electronic configuration of species M2+ is 1s2 2s2 2p6 3s2 3p6 3d6 and its atomic weight is 56. The number of neutrons in the nucleus of species M is
Assertion: The spectrum of He+ is expected to be similar to that of hydrogen.
Reason: He+ is also one electron system.
How many electrons in an atom with atomic number 105 can have (n + 1) = 8?
what are the n and l values for 3px and `"4d"_("x"^2 - "y"^2)` electron?
For each of the following, give the sub level designation, the allowable m values and the number of orbitals
- n = 4, l = 2
- n = 5, l = 3
- n = 7, l = 0
Describe the Aufbau principle.
An atom of an element contains 35 electrons and 45 neutrons. Deduce
- the number of protons
- the electronic configuration for the element
- All the four quantum numbers for the last electron
Calculate the energy required for the process.
\[\ce{He^+_{(g)} -> He^2+_{(g)} + e^-}\]
The ionisation energy for the H atom in its ground state is −13.6 ev atom−1.
An ion with mass number 37 possesses unit negative charge. If the ion contains 11.1% more neutrons than electrons. Find the symbol of the ion.
Identify the missing quantum numbers and the sub energy level
n | l | m | Sub energy level |
? | ? | 0 | 4d |
3 | 1 | 0 | ? |
? | ? | ? | 5p |
? | ? | −2 | 3d |