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Question
State, by writing first four terms, the expansion of the following, where |b| < |a|
`("a" - "b")^(-1/4)`
Solution
`("a" - "b")^(-1/4)`
= `["a"(1 - "b"/"a")]^(-(1)/4)`
= `"a"^(-(1)/4)(1 - "b"/"a")^(-(1)/4)`
= `"a"^(-(1)/4)[1 - (-1/4)"b"/"a" + ((-1/4)(-1/4 - 1))/(2!)("b"/"a")^2 . ((-(1)/4)(-(1)/4 - 1)(-(1)/4 - 2))/(3!)("b"/"a")^3 + ......]`
= `"a"^(-(1)/4)[1 + "b"/(4"a") + ((-(1)/4)(-(5)/4))/2*"b"^2/"a"^2 ((-(1)/4)(-(5)/4)(-(9)/4))/6*"b"^3/"a"^3 + ....]`
= `"a"^(-(1)/4)[1 + "b"/(4"a") + (5"b"^2)/(32"a"^2) + (15"b"^3)/(128"a"^3) + ....]`
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