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Question
State the formula for magnetic induction produced by a current in a circular arc of a wire. Hence find the magnetic induction at the centre of a current carrying circular looр.
Solution
Magnetic Induction Produced by a Current in a Circular Arc of a Wire:
The magnetic induction (magnetic field, B) at the center of a circular arc of a wire carrying a current I is given by:
B = `(μ_0Iθ)/(4R)`
Where,
- B = Magnetic induction at the center
- μ0 = Permeability of free space (4π × 10−7 T·m/A)
- I = Current flowing through the wire (A)
- θ = Angle subtended by the arc at the center (in radians)
- R = Radius of the circular arc (m)
This formula is derived using Biot-Savart’s Law, which states that a small current element produces a magnetic field, and the total field is obtained by integrating over the arc length.
Magnetic Induction at the Center of a Current-Carrying Circular Loop:
For a full circular loop, the subtended angle is:
θ = 2π
Substituting θ = 2π into the formula for a circular arc:
B = `(μ_0I(2pi))/(4R)`
B = `(μ_0I)/(2R)`