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Maharashtra State BoardSSC (English Medium) 6th Standard

Sujata bought a watermelon weighing 4.25 kg and gave 1 kg 750 g to the children in her neighbourhood. How much of it does she have left? - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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Question

Sujata bought a watermelon weighing 4.25 kg and gave 1 kg 750 g to the children in her neighbourhood. How much of it does she have left?

Sum

Solution

Total weight of the watermelon = 4.25 kg

Weight of the watermelon given to the children = 1 kg 750 g
= 1 kg + 750 g
= 1 kg +`750/1000` kg
= 1 kg + 0.75 kg
= 1.75 kg

∴ Weight of the watermelon left with her
= Total weight of the watermelon − Weight of the watermelon given to the children
= 4.25 kg − 1.75 kg
= 2.5 kg

   3 12
   4. 2  5
 −1. 7  5  
   2. 5  0   

Thus, the weight of watermelon left with Sujata is 2.5 kg.

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Chapter 5: Decimal Fractions - Practice Set 14 [Page 31]

APPEARS IN

Balbharati Mathematics [English] 6 Standard Maharashtra State Board
Chapter 5 Decimal Fractions
Practice Set 14 | Q 6 | Page 31
Balbharati Integrated 6 Standard Part 2 [English Medium] Maharashtra State Board
Chapter 3.1 Decimal Fractions
PRACTICE SET 14 | Q 6. | Page 43
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