Question

Suppose an alpha particle accelerated by a potential of V volt is allowed to collide with a nucleus whose atomic number is Z, then the distance of closest approach of alpha particle to the nucleus is ______.

Options

• 14.4 $$\frac{\text{Z}}{\text{V}}$$Å

• 14.4 $$\frac{\text{V}}{\text{Z}}$$Å

• 1.44 $$\frac{\text{Z}}{\text{V}}$$Å

• 1.44 $$\frac{\text{V}}{\text{Z}}$$Å

Answer 1

Suppose an alpha particle accelerated by a potential of V volt is allowed to collide with a nucleus whose atomic number is Z, then the distance of closest approach of alpha particle to the nucleus is 1.44 $$\frac{\text{Z}}{\text{V}}$$Å.