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Question
Suppose we have block of 4 kilogram kept on a horizontal surface and we are applying a horizontal force of 10 newton. Let the coefficient of friction is 0.2. Find the force of friction. Assume that g = 10.
Options
4 newton
8 newton
1 newton
None of these
MCQ
Solution
4 newton
Explanation:
Force of friction = `mu mg`
Where `mu` is the coefficient of static friction.
Given that, `mu` = 0.2, m = 4 kg and g = 10
∴ Force of friction = `0.2 xx 4 xx 10` = 8 N
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