Question

The 24th term of an A.P. exceeds its 19th term by 10, its common difference is ______.

Options

• 5

• 2

• 10

• 1

Answer 1

The 24th term of an A.P. exceeds its 19th term by 10, its common difference is 2.

Explanation:

Let a be the first term and d be the common difference between provided A.P.

Given T₂₄ = T₁₉ + 10

`\implies` a + 23d = a + 18d + 10

`\implies` 23d – 18d = 0

`\implies` 5d = 10

`\implies` d = 2