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Question
The activity of a certain radionuclide decreases to 15 percent of its original value in 10 days. What is its half life?
[ln (0.15) = -1.9]
Options
3.00 days
3.50 days
3.65 days
3.8 days
MCQ
Solution
3.65 days
Explanation:
`t = 1/lambdaIn[N_0/N]`
`lambda = 1/tIn[N_0/N] = 1.9/10` day-1
`t_{1"/"2} = 0.693/lambda = 6.93/1.9 = 3.65` days
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