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The angle of elevation of the top of a tower 30 m high from the foot of another tower in the same plane is 60°, then the distance between the two towers is ____________. -

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Question

The angle of elevation of the top of a tower 30 m high from the foot of another tower in the same plane is 60°, then the distance between the two towers is ____________.

Options

  • `10 sqrt3` m

  • `15 sqrt3` m

  • `12 sqrt3` m

  • 36 m

MCQ
Fill in the Blanks

Solution

The angle of elevation of the top of a tower 30 m high from the foot of another tower in the same plane is 60°, then the distance between the two towers is `underline(10 sqrt3  "m")`.

Explanation:

Observe the figure,

Let the distance between two towers be x m.

`"tan"  60^circ = 30/"x"`

`=> sqrt3 = 30/"x"`

`=> "x" = 30 sqrt3`

`=> "x" = 10sqrt3  "m"`

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