Question

The angle of polarization for a medium is 60°. The critical angle for this will be ______
`(tan 60^circ = sqrt3)`

Options

• `cos^-1(sqrt3)`

• `tan^-1(sqrt3)`

• `sin^{-1^((sqrt3))}`

• `sin^-1(1/sqrt3)`

Answer 1

The angle of polarization for a medium is 60°. The critical angle for this will be `underline(sin^-1(1/sqrt3))`.

Explanation:

`mu = tan60^circ = sqrt3`

`theta = sin^-1(1/mu) = sin^-1(1/sqrt3)`