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Question
The angles of a quadrilateral are in A.P. with common difference 20°. Find its angles.
Solution
Let the four angle of a quadrilateral in A.P. be a, a + 20°, a + 40° and a + 60°
∴ a + (a + 20°) + (a + 40°) + (a + 60°) = 360° ...[Angle sum property]
`=>` 4a + 120° = 360°
`=>` 4a = 240°
`=>` a = 60° ...(1)
Thus, angles of a quarilateral are = a, a + 20°, a + 40° and 60°
= 60°, 80°, 100° and 120°
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