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Question
The approximate change in volume of a cube of side `x` meters coverd by increasing the side by 3% is
Options
`0.06 x^3m^3`
`0.6 x^3m^3`
`0.09 x^3m^3`
`0.9 x^3m^3`
MCQ
Solution
`0.09 x^3m^3`
Explanation:
Side of a cube = `x` meters.
Volume of cube = `x^3`
For `Δx`, ∴ 3% of `x = 0.3x`
Let ΔV be the change = Δv volume
ΔV = `(dv)/(dx) xx Δx = 3x^2 xx Δx`
But `Δx = 0.03x`
ΔV = `.03x`
∴ ΔV = `3x^2 xx 0.03x = 0.09x^3m^3`
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