Advertisements
Advertisements
Question
The area bounded by the X-axis, the curve y = f(x) and the lines x = 1, x = b is equal to `sqrt("b"^2 + 1) - sqrt(2)` for all b > 1, then f(x) is ______.
Options
`sqrt(x - 1)`
`sqrt(x + 1)`
`sqrt(x^2 + 1)`
`x/sqrt(1 + x^2)`
MCQ
Fill in the Blanks
Solution
The area bounded by the X-axis, the curve y = f(x) and the lines x = 1, x = b is equal to `sqrt("b"^2 + 1) - sqrt(2)` for all b > 1, then f(x) is `x/sqrt(1 + x^2)`.
Explanation:
According to the given condition,
`int_1^"b" "f"(x) "d"x = sqrt("b"^2 + 1) - sqrt(2)`
= `sqrt("b"^2 + 1) - sqrt(1 + 1)`
= `[sqrt(x^2 + 1)]_1^"b"`
⇒ f(x) = `x/sqrt(1 + x^2)`
shaalaa.com
Is there an error in this question or solution?