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The area enclosed between the curve y = loge(x + e) and the coordinate axes is ______. -

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Question

The area enclosed between the curve y = loge(x + e) and the coordinate axes is ______.

Options

  • 3 sq. units

  • 4 sq. units

  • 1 sq. unit

  • 2 sq. units

MCQ
Fill in the Blanks

Solution

The area enclosed between the curve y = loge(x + e) and the coordinate axes is 1 sq. unit.

Explanation:

Required area = `int_{1-e}^0log_e(x + e)dx`

= `int_1^e log_e t dt` ....[Put (x + e) = t and dx = dt]

= `[t log_e t - t]_1^e`

= 1 sq. unit

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