Question

The area of cross-sections of the pump plunger and press plunger of a hydraulic press is 0.02 m² and 8 m² respectively. If the hydraulic press overcomes a load of 800 kgf, calculate the force acting on the pump plunger.

Answer 1

Load on the press plunger = L = 800 kgf
Let the effort acting on the pump plunger = E
Area of cross-section of pump plunger = A₁ = 0.02 m²
Area of cross-section of press plunger = A₂ = 8 m²

Now, `"L"/"E"="A"_2/"A"_1`

`800/"E"=8/0.02=800/2=400`

E = `800/400` = 2kgf
⇒ Force acting on the pump plunger = 2kgf