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The arm PQ of a rectangular conductor is moving from x = 0 to x = 2b outwards and then inwards from x = 2b to x = 0 as shown in the figure. A uniform magnetic field perpendicular -

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Question

The arm PQ of a rectangular conductor is moving from x = 0 to x = 2b outwards and then inwards from x = 2b to x = 0 as shown in the figure. A uniform magnetic field perpendicular to the plane is acting from x = 0 to x = b. Identify the graph showing the variation of different quantities with distance.

Options

  • A-Flux, B-EMF, C-Power dissipated

  • A-Power dissipated, B-Flux, C-EMF

  • A-Flux, B-Power, dissipated, C-EMF

  • A-EMF, B-Power dissipated, C-Flux

MCQ

Solution

A-Flux, B-EMF, C-Power dissipated

Explanation:

As the rod moves from x = 0 to x = b, the flux, induced emf, and power dissipated remain constant.

Because no flux changes from x = b to x = 2b, the induced emf and power dissipated are both zero.

So,

A → flux

B → emf

C →power dissipated

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