Question

The average e.m.f induced in a coil in which current change from 0.2 ampere to 0.4 ampere in· 0.1 sec is 1 volt, the self-inductance of the coil is

Options

• 0.2 H

• 0.4 H

• 0.5 H

• 1 H

Answer 1

0.5 H

Explanation:

e = 1 Vol +

`(dI)/(dt) = (0.4 - 0.2)/0.1 = 2AS^-1`

e = `(LdI)/(dt)`

L = `e/((dI)/(dt)) = 1/2` = 0.5 H