Advertisements
Advertisements
Question
The average of two numbers are 20. One number is 24, another number is ____________
Options
16
26
20
40
Solution
16
Explanation;
Hint:
`(x + y)/2` = 20
x + y = 40
24 + y = 40
y = 40 – 24
= 16
APPEARS IN
RELATED QUESTIONS
Following table shows the points of each player scored in four games:
Player | Game 1 | Game 2 | Game 3 | Game 4 |
A | 14 | 16 | 10 | 10 |
B | 0 | 8 | 6 | 4 |
C | 8 | 11 | Did not play | 13 |
Now answer the following questions:
- Find the mean to determine A’s average number of points scored per game.
- To find the mean number of points per game for C, would you divide the total points by 3 or by 4? Why?
- B played in all the four games. How would you find the mean?
- Who is the best performer?
There are 40 students in a class, out of them 15 are boys. The mean of marks obtained by boys is 33 and that for girls is 35. Find out the mean of all students in the class.
The following table shows the number of saplings planted by 30 students. Fill in the boxes and find the average number of saplings planted by each student.
No. of saplings (Scores) xi |
No. of students (frequncy) fi |
fi x xi |
1 | 4 | 4 |
2 | 6 | `square` |
3 | 12 | `square` |
4 | 8 | `square` |
N = `square` | ∑fixi = `square` |
Mean `bar "x"` = `square/"N"`
= `square/square`
= `square`
∴ The average number of trees planted `square`
Find the common difference of the A.P 3, 5, 7, ..........
The mean weight of 4 members of a family is 60 kg. Three of them have the weight 56 kg, 68 kg and 72 kg respectively. Find the weight of the fourth member
If the mean of the following data is 20.2, then find the value of p
Marks | 10 | 15 | 20 | 25 | 30 |
No. of students | 6 | 8 | p | 10 | 6 |
The mean of a, b, c, d and e is 28. If the mean of a, c and e is 24, then mean of b and d is
If the mean of five observations x, x + 2, x + 4, x + 6, x + 8, is 11, then the mean of first three observations is
_______________ is a representative value of the entire data
Find the mean of first six multiples of 4.