Question

The capacity of a parallel plate capacitor is 10 μF when the distance between its plates is 9 cm. What will be its capacity if the distance between the plates is reduced by 6 cm.

Answer 1

Since C ∝ `1/"d"`

∴ `"C"_1/"C"_2 = "d"_2/"d"_1`

∴ `"C"_2 = ("C"_1 xx "d"_1)/("d"_2) = (10 xx 10^-6 xx 9 xx 10^-2)/(3 xx 10^-2)` = 30 μF