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Question
The Cartesian product A × A has 9 elements among which (– 1, 0) and (0, 1) are found. Find the set A and the remaining elements of A × A
Solution
n(A × A) = 9
n(A) = 3
A = {–1, 0, 1}
A × A = {–1, 0, 1} × {–1, 0, 1}
A × A = {(–1, –1) (–1, 0) (–1, 1) (0, –1) (0, 0) (0, 1) (1, –1) (1, 0) (1, 1)}
The remaining elements of A × A = {(–1, –1) (–1, 1) (0, –1) (0, 0) (1, –1) (1, 0) (1, 1)}1
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