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Question
The central fringe of the interference pattern produced by the light of wavelength 6000 Å is found to shift to the position of the fourth bright fringe after a glass plate of refractive index 1.5 is introduced in the path of one of the beams. The thickness of the glass plate would be ______.
Options
4.8 μm
8.23 μm
14.98 μm
3.78 μm
Solution
The central fringe of the interference pattern produced by the light of wavelength 6000 Å is found to shift to the position of the fourth bright fringe after a glass plate of refractive index 1.5 is introduced in the path of one of the beams. The thickness of the glass plate would be 4.8 μm.
Explanation:
Shift in fringe pattern = `(4lambdaD)/d`
Also, shift due to glass plate = `((mu - 1)tD)/d`
`(4lambdaD)/d = ((mu - 1)tD)/d`
`t = (4lambda)/(mu - 1) = (4 xx 6000 xx 10^-10)/(1.5 - 1)`m
= `8 xx 6 xx 10^-7` m
= 4.8 μm