Question

The complex showing a spin-span magnetic moment of 2.82 B.M. is :-

Options

• Ni(CO)₄

• [NiCl]^2–

• Ni(PPh₃)₄

• [Ni(CN)⁴]^2–

Answer 1

[NiCl]^2–

Explanation:

The oxidation state of Ni is +2.

The atomic number of nickel is 28.

Ni = [Ar] 3d⁸4s², Ni² = [Ar]3d⁸

SP³ = Hybridization, tetrahedrol shape.

It has two unpaired electron (n) = 2

MH = ${\displaystyle \sqrt{n(N+2)}=\sqrt{2(2+2)}}$

⇒ BM = 2.82 BM