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Question
The conductivity of 0.02 M solution of NaCl is 2.6 × 10−2 S cm−1. What is its molar conductivity?
Options
1300
2600
13000
130
MCQ
Solution
1300
Explanation:
`∧_"m" = ("k" xx 1000)/("C"("M"))`
= `(2.6 xx 10^-2 xx 1000)/0.02`
= `(26 xx 100)/(0.02 xx 100)`
= `(26 xx 10^2)/2`
= 1300 S cm mol−1
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Electrical Conductance of Solution
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