Advertisements
Advertisements
Question
The count of bacteria in a culture grows by 10% in the first hour, decreases by 8% in the second hour and again increases by 12% in the third hour. If the count of bacteria in the sample is 13125000, what will be the count of bacteria after 3 hours?
Solution
\[Given: \]
\[ R_1 = 10 % \]
\[ R_2 = - 8 % \]
\[ R_3 = 12 % \]
P = Original count of bacteria = 13, 125, 000
We know that:
\[P\left( 1 + \frac{R_1}{100} \right)\left( 1 - \frac{R_2}{100} \right)\left( 1 + \frac{R_3}{100} \right)\]
∴ Bacteria count after three hours \[= 13, 125, 000\left( 1 + \frac{10}{100} \right)\left( 1 - \frac{8}{100} \right)\left( 1 + \frac{12}{100} \right)\]
\[ = 13, 125, 000\left( 1 . 10 \right)\left( 0 . 92 \right)\left( 1 . 12 \right)\]
\[ = 14, 876, 400\]
Thus, the bacteria count after three hours will be 14, 876, 400.
APPEARS IN
RELATED QUESTIONS
The population of a place increased to 54000 in 2003 at a rate of 5% per annum Find the population in 2001.
Find the compound interest on Rs 160000 for one year at the rate of 20% per annum, if the interest is compounded quarterly.
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 5000, Rate = 10 paise per rupee per annum, Time = 2 years
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 12800, Rate = \[7\frac{1}{2} %\], Time = 3 years
The population of a city is 125000. If the annual birth rate and death rate are 5.5% and 3.5% respectively, calculate the population of city after 3 years.
Ms. Cherian purchased a boat for Rs 16000. If the total cost of the boat is depreciating at the rate of 5% per annum, calculate its value after 2 years.
Mohan purchased a house for Rs 30000 and its value is depreciating at the rate of 25% per year. Find the value of the house after 3 years.
The cost price of a machine is 2,50,000. If the rate of depreciation is 10% per year, find the depreciation in price of the machine after two years.
Gautam takes a loan of ₹ 16,000 for 2 years at 15% p.a. compound interest. He repays ₹ 9,000 at the end of the first year. How much must he pay at the end of the second year to clear the debt?
Find the amount and the compound interest on ₹ 4,000 in 2 years, if the rate of interest for the first year is 10% and for the second year is 15%.