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The decreasing order of electrical conductivity of the following aqueous solutions is: A. 0.1 M Formic acid, B. 0.1 M Acetic acid, C. 0.1 M Benzoic acid. -

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Question

The decreasing order of electrical conductivity of the following aqueous solutions is:

  1. 0.1 M Formic acid,
  2. 0.1 M Acetic acid,
  3. 0.1 M Benzoic acid.

Options

  • A > C > B

  • C > B > A

  • A > B > C

  • C > A > B

MCQ

Solution

A > C > B

Explanation:

Order of acidic strength is:

\[\ce{HCOOH > C6H5COOH > CH3COOH}\]

More the acidic strength, more will be the dissociation of acid into ions and more will be the conductivity.

Thus, the order of conductivity will be,

\[\ce{\underset{(A)}{HCOOH} \underset{>}{>} \underset{(C)}{C6H5COOH} \underset{>}{>} \underset{(B)}{CH3COOH}}\]

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