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Question
The degree and order of the differential equation `[1 + (dy/dx)^3]^(7/3) = 7((d^2y)/(dx^2))` respectively are ______.
Options
3 and 7
3 and 2
7 and 3
2 and 3
MCQ
Fill in the Blanks
Solution
The degree and order of the differential equation `[1 + (dy/dx)^3]^(7/3) = 7((d^2y)/(dx^2))` respectively are 3 and 2.
Explanation:
The given differential equation is
`[1 + (dy/dx)^3]^(7/3) = 7((d^2y)/(dx^2))`
After cubing on both sides, we get
`[1 + (dy/dx)^3]^7 = 7^3((d^2y)/(dx^2))^3`
As, highest order derivative is 2, and its degree is 3.
Hence, degree = 3 and order = 2
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