Question

The depth 'd' below the surface of the earth at which acceleration due to gravity becomes `(g/n)` is ______.

R = radius of the earth, 'g' = acceleration due to gravity, n = integer

Options

• `d=1/R((n-1)/n)`

• `d=1/R((n+1)/n)`

• `d=R(n/(n-1))`

• `d=R((n-1)/n)`

Answer 1

The depth 'd' below the surface of the earth at which acceleration due to gravity becomes `(g/n)` is `underline(d=R((n-1)/n))`.

Explanation:

`g_d=g(1-d/R)`

`g/n=g(1-d/R)`

`d/R=1-1/n=(n-1)/n`

`d=R((n-1)/n)`