Advertisements
Advertisements
Question
The diagram shows a uniform metre rule weighing 100gf, pivoted at its centre O. Two weights 150gf and 250gf hang from the point A and B respectively of the metre rule such that OA = 40 cm and OB = 20 cm. Calculate :
the total clockwise moment about O
Solution
Total clockwise moment about O,
=250 gf x 20 cm= 5000 gf cm
APPEARS IN
RELATED QUESTIONS
State two factors on which affect moment of force.
A potter turns his wheel by applying a force through the stick near the rim of wheel.
State Newton's first law of motion. Why is it called the law of inertia?
State the condition when the change in the momentum of a body depends only on the change in its velocity.
A body X of mass 5 kg is moving with velocity 20 m s-2 while another body Y of mass 20 kg is moving with velocity 5 m S-1. Compare the momentum of the two bodies.
A spanner (or wrench) has a long handle. Why?
A, B and C are the three forces each of magnitude 4 N acting in the plane of the paper as shown in Figure. The point O lies in the same plane.
- Which force has the least moment about O? Give a reason.
- Which force has the greatest moment about O? Give a reason.
- Name the forces producing
(a) Clockwise
(b) anticlockwise moments. - What is the resultant torque about the point O?
The moment of a force about axis depends ______.
A uniform metre rule of weight 10gf is pivoted at its 0 mark.
What moment of force depresses the rule?
Calculate the minimum distance between point of application of force and axis of rotation of a rigid body, if a force 125 N produces a moment of force of 25.75 Nm.
