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Question
The differential equation for a2y = log x + b, is ______.
Options
`x (d^2y)/(dx^2) - dy/dx` = 0
`(d^2y)/(dx^2) - x dy/dx` = 0
`x (d^2y)/(dx^2) + x^2 dy/dx` = 0
`x (d^2y)/(dx^2) + dy/dx` = 0
MCQ
Fill in the Blanks
Solution
The differential equation for a2y = log x + b, is `underlinebb(x (d^2y)/(dx^2) + dy/dx = 0)`.
Explanation:
a2y = log x + b
Differentiate w.r.t.x
`a^2 dy/dx = 1/x` ....(1)
Again differentiate w.r.t.x
`a^2 (d^2y)/(dx^2) = - 1/x^2` ....(2)
From (1): a2 = `1/(x dy/dx)`
From (2): `1/(x dy/dx)*(d^2y)/(dx^2) = -1/x^2`
∴ `x(d^2y)/(dx^2) = -dy/dx`, etc.
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Formation of Differential Equations
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