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Question
The differential equation of all parabolas having vertex at the origin and axis along positive Y-axis is ______.
Options
`x^2 dy/dx - y` = 0
`x dy/dx + 2y` = 0
`x dy/dx` = 2y
`x^3 dy/dx` = 3y
MCQ
Fill in the Blanks
Solution
The differential equation of all parabolas having vertex at the origin and axis along positive Y-axis is `underlinebb(x dy/dx = 2y)`.
Explanation:
The general equation of a parabola having vertex at the origin and axis along positive Y-axis is
x2 = 4ay ...(i)
On differentiating equation (i), we get
2x = `4a dy/dx`
`\implies dy/dx = x/(2a)`
`\implies` 2a = `x/(dy/dx)`
Putting the value of 2a in equation (i), we get
x2 = `2(x/(dy/dx))y`
`\implies x dy/dx` = 2y
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Formation of Differential Equations
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